It is known that the area of the triangle formed by the image of the linear function y = - 2x + B [b > 0] and two coordinate axes is equal to 9. Find the solution set of the value of B - 2x + B ≤ 0

It is known that the area of the triangle formed by the image of the linear function y = - 2x + B [b > 0] and two coordinate axes is equal to 9. Find the solution set of the value of B - 2x + B ≤ 0

Because the first-order function is a straight line, it forms a triangle with the coordinate axis and is related to the intercept of the x-axis and y-axis. The focus of the y-axis is (0, b), and the intersection of the Y-axis and the x-axis is (1 / 2B, 0)
Because b > 0
So 1 / 2B > 0
The triangle area is 1 / 2 * 1 / 2B * b = 9
B = 6 or B = - 6, because b > 0, so B = 6
-2x+6≤0
-2x≤-6
X is greater than or equal to 3