The area of the figure enclosed by the curve y = ex, y = E-X, x = 1 is______ .
The area of the figure enclosed by the curve y = ex, y = E-X, x = 1 is ∫ 01 (ex-e-x) DX = (ex + E-X) | 01 = e + e-1-2, so the answer is: e + e-1-2
The area of the figure enclosed by the curve y = ex, y = E-X, x = 1 is ∫ 01 (ex-e-x) DX = (ex + E-X) | 01 = e + e-1-2, so the answer is: e + e-1-2