Find the area of the figure surrounded by X & # 178; + Y & # 178; = 2, X & # 178; + Y & # 178; = 4x, y = x, y = 0

Find the area of the figure surrounded by X & # 178; + Y & # 178; = 2, X & # 178; + Y & # 178; = 4x, y = x, y = 0

It can be seen from the drawing that the enclosed figure is a large sector + an isosceles right triangle - a small sector, the center angle of the small sector = 45 ° and the radius = √ 2, the center angle of the large sector = 90 ° and the radius = 2, the side length of the isosceles right triangle = the radius of the large sector = 2, so the enclosed figure area = π× (2 & # 178;) × (90 / 360) - π× (√ 2)