Given that the angle between the tangent line at point P on parabola y = x ^ 2 and the straight line y = 3x + 1 is (PAI / 4), try to find the coordinates of point P Let P exit slope k | K-3 | / | 1 + 3K |

Given that the angle between the tangent line at point P on parabola y = x ^ 2 and the straight line y = 3x + 1 is (PAI / 4), try to find the coordinates of point P Let P exit slope k | K-3 | / | 1 + 3K |

Let the intersection of y = 3x + 1 and X axis be a, the included angle be Pax, and the slope be tanpax = 3; the tangent slope of p be k = tanpbx, the intersection of y = 3x + 1 and X axis be B, and the included angle be PBX, then the included angle of two lines π / 4 + PBX = Pax, π / 4 = pax-pbx, and both sides are tangent, then Tan π / 4 = Tan (pax-pbx) deduces: 1 = (tanpax tanpbx) / (1 + Tanpa