The square of parabola y = 2px (P > 0), the distance from a point m to the focus is a (a > P / 2), then what is the distance from point m to the collimator? The abscissa of point m is If the distance between a point m and the focus on the parabola y = 2px (P > 0) is a (a > P / 2), what is the distance between the point m and the collimator? What is the abscissa of the point m?

The square of parabola y = 2px (P > 0), the distance from a point m to the focus is a (a > P / 2), then what is the distance from point m to the collimator? The abscissa of point m is If the distance between a point m and the focus on the parabola y = 2px (P > 0) is a (a > P / 2), what is the distance between the point m and the collimator? What is the abscissa of the point m?

A point on a parabola, the distance from the point to the focus = the distance from the point to the directrix
If the distance from m to the focus is a, then the distance from m to the guide line is also a,
Let the abscissa of M be X;
Then x - (- P / 2) = a
So x = A-P / 2
The abscissa of point m is A-P / 2;