F () = x3-x2 + 10, find the tangent equation of curve y = f (x) at point (2, f (2)) Online, etc F () = x3-ax2 + 10, there is at least one real number in the interval (), so that the value range of real number can be obtained.

F () = x3-x2 + 10, find the tangent equation of curve y = f (x) at point (2, f (2)) Online, etc F () = x3-ax2 + 10, there is at least one real number in the interval (), so that the value range of real number can be obtained.

f(2)=8-4+10=14
f'(x)=3x^2-2x
f'(2)=12-4=8
So the tangent equation is
y-f(2)=f'(2)(x-2)
Namely
y-14=8(x-2)
y=8x-2
Hope to help you
The interval behind is incomplete