The square x (1 + LNX) DX of indefinite integral x=

The square x (1 + LNX) DX of indefinite integral x=

What you should say is
∫(x^x)(1+lnx)dx
=∫[e^(xlnx)](1+lnx)dx
=∫[e^(xlnx)]d(xlnx)
=e^(xlnx)+c
=x^x+c