Syndrome: I = ∫ (0, √ (2 Π)) SiNx & #178; DX > 0

Syndrome: I = ∫ (0, √ (2 Π)) SiNx & #178; DX > 0

Let t = x ^ 2
  I=∫(0,(2π))sintd√t
  =sint√t|(0,2π)-∫(0,(2π))cost√tdt
  =-∫(0,(2π))cost√tdt
  I>-∫(0,(2π))costdt=sint|(0,2π)=0
So the conclusion has been proved