Syndrome: I = ∫ (0, √ (2 Π)) SiNx & #178; DX > 0
Let t = x ^ 2
I=∫(0,(2π))sintd√t
=sint√t|(0,2π)-∫(0,(2π))cost√tdt
=-∫(0,(2π))cost√tdt
I>-∫(0,(2π))costdt=sint|(0,2π)=0
So the conclusion has been proved
Let t = x ^ 2
I=∫(0,(2π))sintd√t
=sint√t|(0,2π)-∫(0,(2π))cost√tdt
=-∫(0,(2π))cost√tdt
I>-∫(0,(2π))costdt=sint|(0,2π)=0
So the conclusion has been proved