It is known that the minimum positive period of the function f (x) = 2Sin (ω X - π / 6) sin (ω x + π / 3) (where ω is a normal number and X ∈ R) is π (1) Finding the value of ω (2) In △ ABC, if a < B and f (a) = f (b) = 1 / 2, find BC / ab

It is known that the minimum positive period of the function f (x) = 2Sin (ω X - π / 6) sin (ω x + π / 3) (where ω is a normal number and X ∈ R) is π (1) Finding the value of ω (2) In △ ABC, if a < B and f (a) = f (b) = 1 / 2, find BC / ab

（1）f(X)=2sin(ωx-π/6)sin(ωx+π/3)=-【cos(2ωx+π/6)-cos(-π/2)】=-cos(2ωx+π/6)
So the minimum positive period is 2 π / 2 ω = π
ω=1
(2)f(A)＝f(B)＝1/2
So cos (2x + π / 6) = - 1 / 2
You can calculate a, B, C
So BC / AB = A / C

Elden Ring Premiere

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