5x-8y = 4 - 3x + y = - 0.5, to solve quadratic equation with one variable, we need to solve the process

5x-8y = 4 - 3x + y = - 0.5, to solve quadratic equation with one variable, we need to solve the process

5x-8y=4 ①
-3x + y = - 0.5, y = - 0.5 + 3x 2
② Substituting ①:
5x-8(3x-0.5)=4
-19x=0
x=0
Substituting in 2:
y=-0.5
therefore
x=0
y=-0.5
[questions are welcome]