Find the plane equation that passes through the Y axis and is perpendicular to the plane 5x + 3y-2z + 3 = 0

Find the plane equation that passes through the Y axis and is perpendicular to the plane 5x + 3y-2z + 3 = 0

Let the plane equation be ax + by + CZ + D = 0. Obviously, the normal vector of the plane is V1 = (a, B, c). From the two planes perpendicular, we can get V2 = (5,3, - 2). The point product of V1 and V2 is 0. From the plane passing through the Y axis, we can get three equations that V3 = (0,1,0) is perpendicular to V1 and the plane passes through the point (0,0,0)

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