If the image of function f (x) = sin2x - √ 3cos2x is m, then ① The image m is symmetric with respect to the line x = 11 / 12 π ② The minimum positive period of function f (x) is 2 π ③ The image M can be obtained by translating the image y = 2sin2x π / 3 unit length to the right Which ones are right?

If the image of function f (x) = sin2x - √ 3cos2x is m, then ① The image m is symmetric with respect to the line x = 11 / 12 π ② The minimum positive period of function f (x) is 2 π ③ The image M can be obtained by translating the image y = 2sin2x π / 3 unit length to the right Which ones are right?

Sin2x - √ 3cos2x = 2 (1 / 2sin2x - √ 3 / 2cos2x) = 2 (COS π / 3sin2x sin π / 3cos2x) = 2Sin (2x - π / 3) f (x) = 2Sin (2x - π / 3) ① when x = 11 / 12, 2x - π / 3 = 3 π / 2sin3 π / 2 = - 1, so the image m is symmetrical about the straight line x = 11 / 12, ② t = 2 π / 2 = π error, ③ the image of y = 2sin2x tends to