If the image of a linear function is parallel to the straight line y = 12x − 1, the intersection points with the x-axis and y-axis are a and B respectively, and pass through the points (- 1, - 5), then the points on the line AB (including the end points a and b) whose abscissa and ordinate are integers are () A. Four B. five C. six D. seven

If the image of a linear function is parallel to the straight line y = 12x − 1, the intersection points with the x-axis and y-axis are a and B respectively, and pass through the points (- 1, - 5), then the points on the line AB (including the end points a and b) whose abscissa and ordinate are integers are () A. Four B. five C. six D. seven

Let the line be y = 12x + B, ∵ pass through the point (- 1, - 5), ∵ substitute this point to get - 5 = - 12 + B, the solution is b = - 92, ∵ the line is y = 12x-92. When x = 0, y = - 92; when y = 0, x = 9. So a (9,0), B (0, - 92). From the solution of the line, as long as X is odd, y is an integer, and there are five odd numbers from - 10 to 0, namely - 1 And - 3, - 5, - 7, - 9, so there are 5 points on the line AB (including endpoint a, b) whose abscissa and ordinate are integers