If the center of circle C on the straight line 2x-y-7 = 0 intersects with y axis at two points a (0, - 4), B (0, - 2), then the equation of circle C is?

If the center of circle C on the straight line 2x-y-7 = 0 intersects with y axis at two points a (0, - 4), B (0, - 2), then the equation of circle C is?

The center of the circle (a, b) is on the line 2x-y-7 = 0
b=2a-7
(x-a)^2+(y+7-2a)^2=r^2
Circle and y-axis intersect at two points a (0, - 4), B (0, - 2)
a^2+(-4+7-2a)^2=r^2
a^2+(-2+7-2a)^2=r^2
a=2,b=-3,r^2=5
The equation of circle C: (X-2) ^ 2 + (y + 3) ^ 2 = 5