It is known that f (x) is an odd function, the period is a, and the symmetry axis is 4a?

It is known that f (x) is an odd function, the period is a, and the symmetry axis is 4a?

It is known that x ∈ R, f (x) = - f (- x), f (a + x) = f (A-X);
Solution f [a + (3a + x)] = f [a - (3a + x)]
That is, f (4a + x) = f (- 2a-x) = - f (2a + x) = - f [a + (a + x)] = - f (a + x)
So f (4a + x) = - f (a + x)
f[a+(3a-x)]=f[a-(3a-x)]
That is, f (4a-x) = f (- 2A + x) = - f (2a-x) = - f [a + (A-X)] = - f (A-X)
So f (4a-x) = - f (A-X)
And because f (a + x) = f (A-X), so f (4a + x) = f (4a-x), that is, there is a symmetry axis 4a