1/3+1/15+1/35+1/63+/1+1/99=?

1/3+1/15+1/35+1/63+/1+1/99=?

There's something wrong with the title. I don't think that / 1 is available
The original formula is 1 / (1 * 3) + 1 / (3 * 5) + +1/(9*11)
=2*[1/(1*3)+1/(3*5)+…… +1/(9*11)]/2
=[2/(1*3)+2/(3*5)+…… +2/(9*11)]/2
=(1-1/3+1/3-1/5+1/5-1/7…… +1/9-1/11)/2
=(1-1/11)/2
=5/11