If the volume of the circumscribed sphere of a cube is 36 π, the surface area of the cube is 0

If the volume of the circumscribed sphere of a cube is 36 π, the surface area of the cube is 0

The volume diagonal of a cube is the diameter of the circumscribed sphere, r = (36 π × 3 / (4 π)) cube root = 27, open cube = 3
So the diameter d = 6, let the side length of the cube be x, then √ (X & # 178; + X & # 178; + X & # 178;) = 6,3x & # 178; = 36, X & # 178; = 12, x = 2 √ 3, surface area = (2 √ 3) &# 178; × 6 = 72