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正方體的體對角線是外接球的直徑,r=(36π×3/(4π))立方根=27開立方=3 所以直徑d=6,設正方體的邊長為x,則√(x²;+x²;+x²;)=6,3x²;=36,x²;=12,x=2√3,表面積=(2√3)²;×6=72
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