The graph of a quadratic function passes through (4,0) (2,0) (3,4) Because I don't know how to find the analytic expression of this function with the intersection formula, please write the process... The answer can't be calculated if it's troublesome. Thank you
Let the expression be y = a (x-x1) (x-x2)
Substituting (4,0) (2,0) into the expression, we get the following result:
Y=a(x-4)(x-2)
Substituting (3,4) into the above formula, we get:
4=a(3-4)(3-2)
a=-4
So: the analytic expression of the function is: y = 2 (x-4) (X-2)
y=2x^2-12x+16