The focus F1, F2 and point P of the ellipse x ^ 2 / 9 + y ^ 2 / 2 = 1 are on the ellipse. If the absolute value of Pf1 = 2 ~ then the absolute value of PF2 = angle f1pf2, the size of PF2 is

The focus F1, F2 and point P of the ellipse x ^ 2 / 9 + y ^ 2 / 2 = 1 are on the ellipse. If the absolute value of Pf1 = 2 ~ then the absolute value of PF2 = angle f1pf2, the size of PF2 is

A = 3 B = radical 2
C = root 7
Absolute value of Pf1 + absolute value of PF2 = 2A
PF2 absolute value = 2 * 3-2 = 4
Cos angle f1pf2 = (4 * 4 + 2 * 2-4 * 7) / (2 * 4 * 2)
=-1/2
Angle f1pf2 = 150 degrees