Given that | B-5 | + (a + 6) 2 = 0, a and B are rational numbers, then (a + b) + (a + b) 2 + (a + b) 3 + +(a + b) two thousand nine power + (a + b) 2010 power +(a + b) 2011 power

Given that | B-5 | + (a + 6) 2 = 0, a and B are rational numbers, then (a + b) + (a + b) 2 + (a + b) 3 + +(a + b) two thousand nine power + (a + b) 2010 power +(a + b) 2011 power

|b-5|+(a+6)2=0
Because | B-5 | > = 0, (a + 6) 2 > = 0
So B-5 = 0, a + 6 = 0
a+b=-1
Original formula = - 1 + (- 1) 2 +. + (- 1) 2011 power
=-1