It is known that a, B and C belong to positive real numbers, and it is proved that (BC / a) + (AC / b) + (AB / C) > = a + B + C Second question: A + B + C = 1, proving: radical a + radical B + radical C

It is known that a, B and C belong to positive real numbers, and it is proved that (BC / a) + (AC / b) + (AB / C) > = a + B + C Second question: A + B + C = 1, proving: radical a + radical B + radical C

Because a, B, C ∈ R +, so: (BC / 2a) + (AC / 2b) ≥ 2 √ [(BC / 2a) (AC / 2b)] = 2 √ (ABC ^ 2 / 4AB) = C (BC / 2a) + (AB / 2C) ≥ 2 √ [(BC / 2a) (AB / 2C)] = 2 √ (ACB ^ 2 / 4ac) = B (AC / 2b) + (AB / 2C) ≥ 2 √ [(AC / 2b) (AB / 2C)] = 2 √ (BCA ^ 2 / 4bc) = a

Elden Ring Premiere

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