It is known that the two focuses of hyperbola x ^ 2 - (y ^ 2 / 3) = 1 are F1 and F2 respectively. The slope of a straight line AB passing through the left focus F1 is 3. The area of rtabf2 is calculated Brother, your answer is wrong.

It is known that the two focuses of hyperbola x ^ 2 - (y ^ 2 / 3) = 1 are F1 and F2 respectively. The slope of a straight line AB passing through the left focus F1 is 3. The area of rtabf2 is calculated Brother, your answer is wrong.

S = 2C * (y1-y2) / 2
c=2
Let the linear equation be y = 3x + 6
Substituting into hyperbolic equation
3x^2-9(x^2+4x+4)=3
-6x^2-36x-39=0
x1+x2=-6 x1x2=13/2
So Y1 + y2 = - 6, y1y2 = 9x1x2 + 18 (x1 + x2) + 36
Y1-y2 = √ [(Y1 + Y2) ^ 2-4y1y2] = 3 √ 10
So s = 6 √ 10
This time, it's right. I'm really sorry that the computing power has decreased