Take any two numbers from 1, 3, 5 and 7, and take any two numbers from 2, 4, 6 and 8 to form a four digit number without repetition. The number of four digits divisible by 5 is () A. 120 B. 300 C. 240 D. 108

Take any two numbers from 1, 3, 5 and 7, and take any two numbers from 2, 4, 6 and 8 to form a four digit number without repetition. The number of four digits divisible by 5 is () A. 120 B. 300 C. 240 D. 108

The first step is to put 5 at the bottom of four digits; the second step is to take any one from 1, 3, 7, and there are C31 methods; the third step is to take any two numbers from 2, 4, 6, and 8, and there are C42 methods; the fourth step is to put the three selected numbers on the thousand, hundred, and ten digits of four digits, and there are A33 methods. ∧ therefore, there are c31c42a33 = 108 So D is chosen