Under the standard atmospheric pressure, let 3kg 90 ℃ water absorb 1.5 times 10 of the fifth power Joule heat, how much has the water temperature increased?

Under the standard atmospheric pressure, let 3kg 90 ℃ water absorb 1.5 times 10 of the fifth power Joule heat, how much has the water temperature increased?

Ten degrees centigrade
Δt=Q/cm=1.5*10^5/4.2*10^3*3=10℃