Given a = 2011x + 2010, B = 2011x + 2009, C = 2011x + 2008, find the value of 2A ^ 2 + B ^ 2 + 2C ^ 2-2ac-2ab-2ac Like the title,

Given a = 2011x + 2010, B = 2011x + 2009, C = 2011x + 2008, find the value of 2A ^ 2 + B ^ 2 + 2C ^ 2-2ac-2ab-2ac Like the title,

Is it less? It should be 2B ^ 2
Original formula = (a-b) ^ 2 + (B-C) ^ 2 + (C-A) ^ 2 = 6