Who has the problem of integral multiplication and division The more the better!

Who has the problem of integral multiplication and division The more the better!

Fill in the blanks: (1 point for each blank, A total of 25 points.) 1, - 3x3y2x2y2 =. Am + 1 = a2m2, (m-n) 5 (n-m) 4 = (X-Y) 5 △ = (X-Y) 23. Use scientific counting method to express the following numbers: - 3070000 =, - 0.000075 =, 0.12 =. 4. Write the original numbers of the following scientific counting method. 4.017 × 104 =, - 3.76 × 10-3 =. 5, (A8 △ a2a3) 2 =, (2x-3y) (- 3y-2x) = (- 1-A) 2 =. 6, (- 5a5b4) 2 ^ (- 2a2b) 3 =, (- x + y) 2 = (a-b-c) 2 =, (4m3-2m2 + m) ^ (- 2m) = 7. If the division formula is x2-x + 1, the quotient formula is x + 1, and the remainder formula is 3x, then the division formula is 8. If 5m =, 5N = 3, then 5m-2n =, 52m + n =. 9. If X-Y = 3, xy = 2, then x + y =, if x + = - 2, If (2x-3) (x + 4) = 2x2 + ax + B, then a =, B =. 11. If A2N = 3, then (2a3n) 2-3 (A2) 2n =. 2. Multiple choice questions: (16 points) 1. The correct calculation of the following questions is () a, a2a4 = a8b, (- 2A2) 3 = - 6a6c, (an + 1) 2 = A2N + 1D, anaan-1 = a2n2, if (x-a) 2 = x2 + X +, then a = () C. D, - 3, if x2 + 6xy + m is a complete square, then M = (). A, 9y2 B, 3y2 C, Y2 D, 6y2 4. To make the formula x2 + Y2 a complete square, then add (). A, B, C, D, 5, known as a3x + 1a2y-1 = A3, b3xb = b2y, then x, y are (). A, x = 3, y = 1b, x = 2, y = 1C, x =, y = 1D, x =, x =, If y = 16, calculate (- 2) 101 + (- 2) 100 = () a, 2100 B, - 1 C, - 2 D, - 2100 7, the product of known polynomial x2 + ax + B and x2-2x-3 does not contain X3 and X2 terms, then the value of a and B is (). A, a = 2, B = 7, B, a = - 2, B = - 3, C, a = 3, B = 7 d, a = 3, B = 4 8, when x = - 3, the value of polynomial ax5-bx3 + cx-8 is 8, then when x = 3, its value is 8（ ）A, 8 B, - 8 C, 24 D, - 24 3, calculate the following questions: (25 points) 1, (- 2) 3 × (- 2) - 2 - (- 32) / (- 2) + (- 100) 0 2, xx4 + X2 (x3-1) - 2x3 (x + 1) 2 3, (3x3) 2 (- 2Y2) 5 × (- 6xy4) 4, (2a-b + 1) (2a + B-1) - (B + 1) 2 5, A2 (A-1) (3a-5) / (- A2) - (6a2-4a) / - 2A 4、 To solve an equation or inequality or a system of equations: (15 points) 1, (3x-5) (5 + 3x) - (3x-1) 2 = 102, (2x + 3) 2 - (2x + 3) (2x-5) < 7x + 6 3, 5, first simplify, then evaluate (15 points) 1, [(2xy-3) (2XY + 3) + (XY + 3) 2] / XY, where x =, y = - 22, 8m2-5m (- M + 3n) + 4m (- 4m-n), where M = 2, N = - 1 3, (8x2 + 4x + 1) (- 8x2 + 4x-1) where x = 6, two two digit ten digit numbers are the same, one digit number is 6, the other digit number is 4, their square difference is 220, find this two digit number? (4 points)