Given that the domain of y = FX + 1 is [- 2,3], then the domain of y = f2x-1 is?. why not directly - 2 ≤ x ≤ 3?

Given that the domain of y = FX + 1 is [- 2,3], then the domain of y = f2x-1 is?. why not directly - 2 ≤ x ≤ 3?

Because the domain of the function y = f (x + 1) is [- 2,3],
So the definition field of function f (x) is [- 2 + 1,3 + 1] = [- 1,4]
So for y = f (2x-1),
-1=