Given the function f (x) = sin (Wx + π / 6) + sin (Wx - π / 6) + 2cos ^ 2 (Wx / 2), W is the smallest positive integer that makes f (x) get the maximum value at π / 3 Let the three sides a, B, C of △ ABC satisfy B ^ 2 = AC, and the set of values of angle o of edge B is p, when x ∈ P is the range of F (x)

Given the function f (x) = sin (Wx + π / 6) + sin (Wx - π / 6) + 2cos ^ 2 (Wx / 2), W is the smallest positive integer that makes f (x) get the maximum value at π / 3 Let the three sides a, B, C of △ ABC satisfy B ^ 2 = AC, and the set of values of angle o of edge B is p, when x ∈ P is the range of F (x)

F (x) = 2Sin (2 ω X / 2) cos π / 3 + 1 + cos ω x = √ 3sin ω x + cos ω x + 1 = 2Sin (ω x + π / 6) + 1. Because the maximum value is obtained at π / 3, we put ω into f (x) = 2Sin ω (x + π / (6 ω)) + 1. We can see that it is obtained by reducing the abscissa of F (x) = SiNx image by ω times, and then shifting π / (6 ω) to the left, so (...)