Let f (x) = XG (x), the tangent equation of curve y = g (x) at point (2, G (2)) be y = 1-x, then the tangent equation of curve y = f (x) at point (2, f (2)) is y = 1-x

Let f (x) = XG (x), the tangent equation of curve y = g (x) at point (2, G (2)) be y = 1-x, then the tangent equation of curve y = f (x) at point (2, f (2)) is y = 1-x

The tangent equation of the curve y = g (x) at the point (2, G (2)) is y = 1-x, then the point should also be on the tangent, so the coordinates of the point are brought into the tangent equation: G (2) = 1-2 = - 1, so the tangent equation of the curve y = g (x) at the point (2, - 1) is y = 1-x, then f (2) = 2g (2) = - 2, then the curve y = f (x) at the point (2, f (2))