If f (x) - G (x) + X & sup2;, the tangent equation of curve Y-G (x) at point (1, G (1)) is y = 2x + 1 Let f (x) = g (x) + X2, the tangent equation of curve y = g (x) at point (1, G (1)) be y = 2x + 1, then the tangent equation of curve y = f (x) at point (1, f (1)) is y = 2x + 1-----

If f (x) - G (x) + X & sup2;, the tangent equation of curve Y-G (x) at point (1, G (1)) is y = 2x + 1 Let f (x) = g (x) + X2, the tangent equation of curve y = g (x) at point (1, G (1)) be y = 2x + 1, then the tangent equation of curve y = f (x) at point (1, f (1)) is y = 2x + 1-----

The tangent equation of curve y = g (x) at point (1, G (1)) is y = 2x + 1, then G '(1) = 2, G (1) = 2 * 1 + 1 = 3, so f' (x) = g '(x) + 2x, so the slope of tangent at (1, f (1)) is k = f' (1) = g '(1) + 2 * 1 = 2 + 2 = 4, f (1) = g (1) + 1 ^ 2 = 3 + 1 = 4, so the tangent equation is: y-4 = 4 (x-1), that is: y = 4x