The tangent equation of curve y = xex + 2x + 1 at point (0,1) is () A. y=-3x+1B. y=3x+1C. y=2x+2D. y=-2x+2

The tangent equation of curve y = xex + 2x + 1 at point (0,1) is () A. y=-3x+1B. y=3x+1C. y=2x+2D. y=-2x+2

When x = 0, the tangent equation of Y '= (1 + x) ex + 2 is Y-1 = 3x, that is, y = 3x + 1