For a linear function y = - 2x + 3, the value range of the independent variable X of its image in the first quadrant is? The answer is 0 < x < 3 / 2,

For a linear function y = - 2x + 3, the value range of the independent variable X of its image in the first quadrant is? The answer is 0 < x < 3 / 2,

-2X + 3 > 0 x < 3 / 2
The first quadrant x is greater than 0
So 0 < x < 3 / 2