To solve the equation: 1 / 3 [x minus 1 / 2 (x-1)] = 2 / 3 (x minus 1 / 2)]

To solve the equation: 1 / 3 [x minus 1 / 2 (x-1)] = 2 / 3 (x minus 1 / 2)]

1/3[x-1/2(x-1)]=2/3(x-1/2)
[x-1/2(x-1)]=2(x-1/2)
x-x/2+1/2=2x-1
x=1