In the known triangle ABC, BC = x, AC = 2, B = 45 degrees, if the triangle has two solutions, then the value range of X is?

In the known triangle ABC, BC = x, AC = 2, B = 45 degrees, if the triangle has two solutions, then the value range of X is?

(2,2 √ 2) draw an angle of 45 ° with the vertex B. take the line BC = x on one side. Take point C as the center of the circle and the radius is 2. Because there are two solutions, the circle should intersect with the other side. If there is no solution, it is separated. If there is a solution, it is tangent