The first step: take a natural number N1 = 5, calculate the square of N1 + 1 to get A1; the second step: calculate the sum of all numbers of A1 to get N2, and calculate the square of N2 + 1 to get A2 Step 3: calculate N3 of the sum of the numbers of A2, and then calculate the square of N3 to get A3 a2011=?

The first step: take a natural number N1 = 5, calculate the square of N1 + 1 to get A1; the second step: calculate the sum of all numbers of A1 to get N2, and calculate the square of N2 + 1 to get A2 Step 3: calculate N3 of the sum of the numbers of A2, and then calculate the square of N3 to get A3 a2011=?

Square of N1 + 1 = A1 = 26
The sum of the numbers of A1 = N2 = 8,
Square of N2 + 1 = A2 = 65
The sum of A2 = N3 = 1211 + 2 + 1 = 5
So every three cycles is a cycle
2011 △ 3 = 670 + 1
So a2011 = 26