A village wants to buy three kinds of trees. It is known that the price ratio of three kinds of trees is 2:2:3, and each tree is 200 yuan. Now it plans to use 210000 yuan to buy a total of 1000 trees If you buy tree a twice as much as tree B, and you just run out of money, how many trees can you buy If the purchase price of 10120 yuan is increased, how many trees can C buy at most on the premise that the total tree purchase remains unchanged?

A village wants to buy three kinds of trees. It is known that the price ratio of three kinds of trees is 2:2:3, and each tree is 200 yuan. Now it plans to use 210000 yuan to buy a total of 1000 trees If you buy tree a twice as much as tree B, and you just run out of money, how many trees can you buy If the purchase price of 10120 yuan is increased, how many trees can C buy at most on the premise that the total tree purchase remains unchanged?

If you buy x trees of type B, you will buy 2x trees of type A and (1000-3x) trees of type C
200×2x+200x+300（1000-3x）=210000,
The solution is x = 30,
∴2x=600,1000-3x=100,
A: we can buy 600 A-type trees, 300 B-type trees and 100 C-type trees;
If y trees of C species are purchased, there will be (1000-y) trees of a and B species
200（1000-y）+300y?210000+10120,
The solution is y ≤ 201.2,
∵ y is a positive integer,
The maximum value of Y is 201,
A: you can buy 201 C trees at most