Three points a (0,2,3), B (- 2,1,6), C (1, - 1,5) are known. If | a | = √ 3, and a is perpendicular to ab vector and AC vector respectively, then

Three points a (0,2,3), B (- 2,1,6), C (1, - 1,5) are known. If | a | = √ 3, and a is perpendicular to ab vector and AC vector respectively, then

Let a = (x, y, z)
∵a⊥AB,a⊥AC
∴-2x-y-3z=0,x-3y+2z=0
And x ^ 2 + y ^ 2 + Z ^ 2 = 3
Ψ x = y = z = 1 or x = y = z = - 1
A = {1,1,1} or {- 1, - 1, - 1}

Elden Ring Premiere

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