P is the point on the ellipse x ^ 2 / 25 + y ^ 2 / 16 = 1, F1 and F2 are the left and right focal points, and the angle f1pf2 = 60 °, then what is the area of △ pf1f2

P is the point on the ellipse x ^ 2 / 25 + y ^ 2 / 16 = 1, F1 and F2 are the left and right focal points, and the angle f1pf2 = 60 °, then what is the area of △ pf1f2

There is a formula
The triangle formed by a point and two focuses on an ellipse is called the focus triangle
The focus triangle has an area formula, which is s = B ^ 2tan θ / 2 (the square of B multiplied by the tangent of θ / 2, B is the length of the short half axis, and θ is ∠ f1pf2)
∴S=16×√3/3=16√3/3