Let the sum of the first n terms of the equal ratio sequence {an} be Sn, A1 = 2011, and an + 2An + 1 + an + 2 = 0 (n ∈ n ·), then s2012=______ .

Let the sum of the first n terms of the equal ratio sequence {an} be Sn, A1 = 2011, and an + 2An + 1 + an + 2 = 0 (n ∈ n ·), then s2012=______ .

Let the common ratio of the equal ratio sequence {an} be q ∵ an + 2An + 1 + an + 2 = 0 (n ∈ n ·) ∵ an + 2anq + anq2 = 0 ∵ an ≠ 0 ∵ (Q + 1) 2 = 0 ∵ q = - 1 ∵ A1 = 2011 ∵ s2012 = 2012 [1 − (− 1) 2012] 1 + 1 = 0, so the answer is 0