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設等比數列{an}的公比為q∵an+2an+1+an+2=0(n∈N•)∴an+2anq+anq2=0∵an≠0∴(q+1)2=0∴q=-1∵a1=2011∴S2012=2012[1−(−1)2012]1+1=0故答案為0
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