How to deal with the problem that the equal sign can't be obtained when seeking the maximum value in the basic inequality Root XY ≥ 2 root 3 / 5 If and only if x = y = 2 radical 3 / 5, the minimum value of radical XY is 2 radical 3 / 5, At the same time, if 3x = 4Y (x ≠ y), what is the minimum value of root XY? Can only the above conditions be answered? If x, y satisfy x + 3Y = 5xy, then the minimum value of 3x + 4Y is?

How to deal with the problem that the equal sign can't be obtained when seeking the maximum value in the basic inequality Root XY ≥ 2 root 3 / 5 If and only if x = y = 2 radical 3 / 5, the minimum value of radical XY is 2 radical 3 / 5, At the same time, if 3x = 4Y (x ≠ y), what is the minimum value of root XY? Can only the above conditions be answered? If x, y satisfy x + 3Y = 5xy, then the minimum value of 3x + 4Y is?

Since x = y = 2 radical 3 / 5, then XY ≥ 12 / 5
Only these conditions are not enough. XY can be taken arbitrarily
General inequalities have many unknowns and restrictive conditions, such as 3x + 4Y = 10. Such conditions as 3x = 4Y are not restrictive conditions, and virtually turn two unknowns into one