A 2-meter-long cuboid wood has a cross-sectional area of 16 square decimeters. How many cubic meters is its volume? Determinant

A 2-meter-long cuboid wood has a cross-sectional area of 16 square decimeters. How many cubic meters is its volume? Determinant

16 / 100 * 2 = 0.32 M3

The volume of a cuboid wood is 4.5 cubic decimeter, the cross-sectional area is 0.5 cubic decimeter, and the length of the wood is 5______ Decimeter

4.5 △ 0.5 = 9 (decimeter) answer: the length of wood is 9 decimeters. So the answer is: 9

When a 2 meter long cuboid wood is sawed into three sections, the surface area increases by 28.8 square decimeters, and the original volume of the wood is () cubic decimeters

After sawing into 3 sections, there are 4 more sections with a total area of 28.8%
If the section area is s, then 4S = 28.8
S=7.2
So cuboid volume = section area * length = s * 2 = 14.4

If △ ABC ~ △ DEF is known, AB: de = 1:2, then the perimeter ratio of △ ABC to △ DEF is? And the area ratio is?
If BC = 5cm, then what is ef? If angle a is equal to 32 ° and angle B is equal to 50 ° then what is angle f

Perimeter ratio 1:2. Area ratio 1:4
EF = 10. ∠ f = 98 degrees

Imagine how to write a composition!
You are an astronaut of space2. You drive your spaceship to the moon, where you meet Chang'e. write a diary and write down the scene when you see Chang'e. who can help me put forward my ideas or write about it!

The appearance of Chang'e, the sound of your conversation
Have you seen the jade rabbit Chang'e take you to visit the moon
And so on

New mathematics curriculum standard synchronous unit exercise 29 pages contact development
Arrange three numbers in sequence: 3, 9, 8. For any two adjacent numbers, subtract the number on the left from the tree on the right, and write the difference between the two numbers to generate a new number string: 3, 6, 9, - 1, 8. This is called the first operation. After the second operation, a new number string can be generated: 3, 3, 6, 3, 9, - 10, - 1, 9, 8
(1) What is the sum of the new numbers added after the first operation?
(2) What is the sum of the number of strings obtained in the second operation compared with those obtained in the first operation?
(3) Conjecture: what is the sum of the new numbers of the number strings obtained after the 2009 operation compared with the number strings obtained after the 2008 operation?
(4) Use your guess to calculate the sum of all the numbers after the 2009 operation
Seventh grade volume I problem. Can solve, it is best to write down the process. Write down online conversation

(1)5
(2)5
(3)5
(4) The first three numbers add up to 20, and then add up to 5 each time. In 2009, a total of 2008x5 = 10040 is added, and the first number is 10060
The first two steps can be obtained by subtracting the number in front. They are all regular questions. It's easy to pay attention to the first few questions in the future

The following is a plan of a rectangular foundation of a construction site, with a scale of 1:2000. The length in the plan is 2.6cm, and the width is 1.5?
A pair of cogging gears, the big gear has 40 teeth, 105 revolutions per minute, the small gear has 10 teeth, how many revolutions per minute?

So the actual length is 2.6 × 2000 = 52 meters
The width is 1.5 × 2000 = 30 meters
The area is 52 × 30 = 1560 square meters
The big gear turns 105 × 40 = 4200 teeth per minute
The number of revolutions of the pinion is 4200 / 10 = 420 revolutions

How to learn the equation of one variable and one degree in seventh grade mathematics

The general solution is as follows
1. To remove the denominator: multiply the least common multiple of each denominator on both sides of the equation (items without denominator should also be multiplied);
2. Remove brackets: remove the brackets first, then the brackets, and finally the braces; (remember to change the sign if there is a minus sign outside the brackets)
3. Term shifting: move all the terms containing unknowns to one side of the equation, and all other terms to the other side of the equation; the term shifting should be signed
4. Merge similar terms: change the equation into the form AX = B (a ≠ 0);
5. Change the coefficient into 1: divide the coefficient a of the unknown number on both sides of the equation to get the solution x = B / A
An important way to solve the application problem of linear equation of one variable is as follows:
1. Examine the topic carefully (examine the topic)
2. Analysis of known and unknown quantities
3. Find a suitable equivalent relationship
4. Set an appropriate unknown
5. List reasonable equations (expressions)
Solving equations (solving problems)
⒎ test
8. Write the answer (answer)

Divide the figure into four equal size and shape blocks

According to the analysis, the drawing is as follows:

Give some examples of translation in life______ ．

All the movements in line with the nature of translation are translation, such as the up and down movement of the elevator, the driving of the car on the straight road, the opening and closing of the glass sliding door, etc. so the answer is: the up and down movement of the elevator, the driving of the car on the straight road, the opening and closing of the glass sliding door, etc