A curve C: y ^ 2 = x + 1 and a fixed point a (3,1), B is any point on the curve C. If AP vector = 2 times Pb vector, when point B moves on the curve C, Given the curve C: y ^ 2 = x + 1 and the fixed point a (3,1), B is any point on the curve C. If AP vector = 2 times Pb vector, when point B moves on the curve C, the trajectory equation of point P is obtained come

Let P (x, y) B (XB, Yb) take XB and Yb into parabola because AP vector = 2 times Pb vector, so x = (3 + 2xb) / (1 + 2) y = (1 + 2yb) / (1 + 2) so XB = (3x-3) / 2 Yb = (3y-1) / 2, get ((3y-1) / 2) ^ 2 = (3x-3) / 2 + 1, sort out 9y ^ 2-6y-6x + 1 = 0, so P point trajectory equation is 9y ^ 2-6y-6x + 1 = 0

The following equations are transformed into two forms, one of which represents the other with the algebraic expression of the unknown
3x+y-1=0
x-3y+12=0

1、3x+y-1=0
y=1-3x
3x=1-y
x=1/3-y/3
2、-3y=-12-x
y=4+x/3
x=3y-12

Let the quadrilateral ABCD be similar to the quadrilateral a1b1c1d1, and point a and point A1, point B and point B1, point C and point C1, and point D and point D1 be corresponding points,
Given AB = 10, BC = 8, CD = 8, ad = 6, A1B1 = 8, find the perimeter of the quadrilateral a1b1c1d1

Circumference ABCD = 10 + 8 + 8 + 6 = 32
The quadrilateral ABCD is similar to the quadrilateral a1b1c1d1
A and A1, B and B1, C and C1 are corresponding points
｜ AB: A1B1 = perimeter ABCD: perimeter a1b1c1d1
10: 8 = 32: perimeter a1b1c1d1
Perimeter a1b1c1d1 = 128 / 5

The sequence is square, A1 = 1, A2 = 4, A3 = 9
How to find the sum of the first n terms of a sequence and the SN general term formula

By using the identity (n + 1) &# 179; = n & # 179; + 3N & # 178; + 3N + 1, we can get the following results:
(n+1)³-n³=3n²+3n+1,
n³-(n-1)³=3(n-1)²+3(n-1)+1
.
3³-2³=3*(2²)+3*2+1
2³-1³=3*(1²)+3*1+1.
Add the two ends of the n equations respectively, and the result is as follows:
(n+1)³-1=3(1²+2²+3²+.+n²)+3(1+2+3+...+n)+n,
Since 1 + 2 + 3 +... + n = (n + 1) n / 2,
Substituting the above formula, we get the following result:
n³+3n²+3n=3(1²+2²+3²+.+n²)+3(n+1)n/2+n
After finishing, we can get the following conclusions
1²+2²+3²+.+n²=n(n+1)(2n+1)/6

In the following example, which polynomials are completely squared? Please factorize the polynomials that are completely squared
(1) The square of X - x + 1 / 4
(2) One fourth of the square of M + 3MN + 9N
(3) The square of 9a, the square of B - 3AB + 1
(4) The sixth power of X - the third power of 10x - 25
2、 Divide the following into factors
(1) The square of X - 12xy + 36Y
(2) The fourth power of 16A + the square of 24a + the square of B + the fourth power of 9b
(3) The square of - 2xy-x - the square of Y
(4) Square of 4-12 (X-Y) + 9 (X-Y)
I'll go through the steps

(1)x^2-x+1/4=(x-1/2)^2
(2)1/4m^2+3mn+9n^2=1/4(m^2+12mn+36n^2)=1/4(m+6n)^2
(3) 9A ^ 2B ^ 2-3ab + 1 is not a complete square
(4) X ^ 6-10x ^ 3-25 is not a perfect square
（1）x^2-12xy+36y^2=(x-6)^2
(2)16a^4+24a^2b^2+9b^4=(4a^2+3b^2)^2
(3)）-2xy-x^2-y^2=-(2xy+x^2+y^2)=-(x+y)^2
(4)4-12（x-y）+9（x-y）^2=[3(x-y)-2]^2

If | A-2 | + b2-2b + 1 = 0, then a + B=______ ．

∵|a-2 | + b2-2b + 1 = 0, ∵|a-2 | + (B-1) 2 = 0, ∵|a-2 | = 0, (B-1) 2 = 0, ∵ a = 2, B = 1, ∵ a + B = 2 + 1 = 3

If the distance between two opposite sides of a parallelogram is 2cm and 4cm respectively, and its perimeter is 18cm, then the area of the parallelogram is

2(a+b) = 18
a+b = 9
a/2 = b/4
b = 2a
a =3
b =6
The area of this parallelogram
= 6 ×2
=12 square centimeters

1.5 (10-x) = 3
Why isn't 1.5 (10-x) = 3 & quot; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 2 or & quot; 1.5 (10-x) = 3 & quot;
1.5x10-1.5x=3 1.5(10-x)/1.5=3/1.5
15-1.5x=3 10-x=2
15-1.5x/1.5=3/1.5 10-x+10=2+10
15-x=2 x=12?
15-x+15=15+2
x=17?
&The third is the & quot; and the & quot; 3 & quot; and the & quot; 3 & quot; and the & quot; 3 & quot; 3 & quot; 1.5 (10-x) (10-10-10-10-10-10-10-10-10-10-x) = 3 & quot; & nbsp; & nbsp; & & nbsp & nbsp; & & nbsp & nbsp & nbsp; & & nbsp & nbsp; & & nbsp & nbsp & nbsp & nbsp; & & nbsp & nbsp & nbsp; & & nbsp & nbsp & nbsp & nbsp & nbsp & nbsp & nbsp & nbsp & nbsp & nbsp & nbsp & nbsp & nbsp & nbsp & & nbsp & nbsp & nbsp & nbsp & nbsp & nbsp & nbsp & nbsp & nbsp & nbsp & nbsp & nbsp & nbsp & nbsp & nbsp & nbsp & nbsp & nbsp & nbsp & nbsp & nbsp & nbsp & nbsp & nbsp & nbsp & nbsp & nbsp & nbsp & nbsp & nbsp & nbsp & nbsp & nbsp & nbsp & nbsp & nbsp & nbsp & nbsp & nbsp & nbsp & nbsp & nbsp & nbsp & nbsp & nbsp & nbsp nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 3 + 1.5x = 15 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 3+1.5x-3=15-3 1.5x=12 1.5x÷1.5=12÷1.5 x=8?
Why are 1 and 2 wrong? What's wrong? Isn't that what we do?
Why is 3 right and why?
I'm not very good at solving equations. I tried a lot of methods to help you practice every day, but I still didn't succeed. What should I do?
We still have the last five days to take the exam, which affects the entrance of middle school,
I hope you can help me. I'd appreciate it very much, but please don't talk about what everyone knows

In the first fourth line divided by 1.5, 15 is not divided
The second penultimate line 10-x + 10 is not x, but 20-x
Both sides of the equation should add, subtract, multiply and divide at the same time
Come on, work hard

The area of each surface of p-abc is s △ ABC = 6, s △ PAB = 3, s △ PBC = 4, s △ PCA = 5, and the dihedral angles of each side and bottom are equal, so the volume is calculated

Because the dihedral angles of p-abc are equal to the dihedral angles of the bottom, it is deduced that the height of each side of p-abc is equal, and the vertical distance of ABC on the bottom is equal. The vertical center is the projection of point P on ABC on the bottom. Because △ PAB = 3, s △ PBC = 4, s △ PCA = 5, the ratio of AB to BC is 3 to 4 to 5

The solution equation is 1.12 / (0.5x-1) = 4.9.8 * one and half - x * 50% = 2.4
2.12x-3=8x+17
3.25.2x/3=6.34
4.9.8 one and half - x * 50% = 2.4
The first question is 12 / (0.5x-1) = 4

I can't see the fourth one clearly
0.5x-1=12/4 12x-8x=17+3 25.2x=6.3*4*3
0.5x=3+1 4x=20 25.2x=75.6
x=8 x=5 x=3

The following equations are transformed into two forms, one of which represents the other with the algebraic expression of the unknown 3x+y-1=0 x-3y+12=0

Let the quadrilateral ABCD be similar to the quadrilateral a1b1c1d1, and point a and point A1, point B and point B1, point C and point C1, and point D and point D1 be corresponding points, Given AB = 10, BC = 8, CD = 8, ad = 6, A1B1 = 8, find the perimeter of the quadrilateral a1b1c1d1

The sequence is square, A1 = 1, A2 = 4, A3 = 9 How to find the sum of the first n terms of a sequence and the SN general term formula