Let X and y satisfy 3

Let X and y satisfy 3

Obviously, XY ≠ 0, because 3 ≤ XY ^ 2 ≤ 8, 3 / y ^ 2 ≤ x ≤ 8 / y ^ 2, so x > 0. Similarly, Y > 0, let a = x ^ 3 / y ^ 4, x ^ 3 = ay ^ 4, because 3 ≤ XY ^ 2 ≤ 8, so 3 ^ 3 ≤ x ^ 3 * y ^ 6 ≤ 8 ^ 3 = 2 ^ 9, 3 ^ 3 ≤ ay ^ 10 ≤ 2 ^ 9 (1) Because 4 ≤ x ^ 2 / Y ≤ 9, 4 ^ 3 ≤ x ^ 6 * y ^ (- 3) ≤ 9 ^ 3 = 3 ^ 6, 4 ^ 3 ≤ a ^ 2 * y ^ 5 ≤ 3 ^ 6, 4 ^ 6 ≤ a ^ 4 * y ^ 10 ≤ 3 ^ 12, 3 ^ (- 12) ≤ a ^ (- 4) * y ^ (- 10) ≤ 4 ^ (- 6) = 2 ^ (- 12) 3 ^ (- 12) ≤ a ^ (- 4) * y ^ (- 10) ≤ 2 ^ (- 12) (2) (1) (2) multiplication of two sides: 3 ^ 3 * 3 ^ (- 12) ≤ ay ^ 10 * a ^ (- 4) * y ^ (- 10) ≤ 2 ^ 9 * 2 ^ (- 12) 3 ^ (- 9) ≤ a ^ (- 3) ≤ 2 ^ (- 3) 2 ^ 3 ≤ a ^ 3 ≤ 3 ^ 9 2 ≤ a ≤ 3 ^ 3 = 27 maximum 27

Given that a and B are reciprocal, C and D are opposite, and M is the largest negative number, try to find the value of M / 3 + 8ab-5 / 4C + 4d-23

It is known that a and B are reciprocal, C and D are opposite, and M is the largest negative integer,
ab=1
c+d=0
m=-1
3 / M + 8ab-5 / 4C + 4d-23
=-1/3+8-4/5*0-23
=-1/3+8-23
=-15 and 1 / 3

Given that X1 and X2 are the two roots of the equation x & # 178; - 2x-1 = 0, then 1 / 1 of X1 + 1 / 2 of x2 equals 0

The two different zeros of the function f (x) = x ^ 2 + (M + 1) x + m are X1 and X2, and the sum of squares of the reciprocal of the two zeros is 2

From the analytic expression of the function, we can find that its two roots are: x = - m, x = - 1
We can get m * m = 1, M = 1, M = - 1 directly

On the inequality system of X 2x > 6, x < m has no solution, then the value range of M is

The system of inequalities 2x > 6, x > 3 for X
If x ＜ m has no solution, then the value range of M is
m

Finding vertex coordinates of quadratic function y = x ^ 2-2x-1

y=X^2-2x-1
＝X^2-2x+1-1-1
＝（x-1）^2-2
So the vertex is: (1, - 2)

Solve the equation: 0.2x8/x = 0.24, X is the multiplier sign, X is the unknown number

0.2X8/x=0.24
1.6/x=0.24
x=1.6/0.24
x=20/3

We know the equation KX + M = (2k-1) x + 4 about X, when k____ ,m_____ The equation has a unique solution

kx+m=(2k-1)x+4
(1-k)x=4-m
1-k ≠ 0,4-m is arbitrary
The equation has a unique solution
therefore
k≠1
M is any value

3 / 2x = 16-x to solve the equation

x+1.5x=16
2.5x=16
X = 6.4 or x = 32 / 5

Calculation: 3-x / 10 / X-1 / (x > 5)

(2x / 3 radical 9x) + (6x radical X / 4) - (x ^ 3 radical 1 / x ^ 3)
=(2x/3√9x)+6x√x/4-x^3√1/x^3
=2x/9√x+3x√x-x^3√(1/x)/x
=2√x/9+3x√x-x√x
=2√x/9+2x√x