The sum of the two primes is 2001, and the product of the two primes is______ ．

The sum of the two primes is 2001, and the product of the two primes is______ ．

Because the sum of two prime numbers is odd, one prime number must be odd and the other even. Because 2 is the only even prime number, the other prime number is 1999, so their product is 2 × 1999 = 3998

1. The sum of two prime numbers is 15, and their product is [

2+13=15 2x13=26 9 0.5

The sum of two primes is 15. What's the product?
Urgent

2+13 2*13=26

There are two prime numbers whose sum is 8 and their product is 15. These two prime numbers are

3 and 5
The two numbers must be less than 8, so there are prime numbers 2, 3, 5 and 7 left

P. Q is any two points on the straight line Mn, a is the midpoint of MP, B is the midpoint of QN, if AB = m, PQ = n, what is the length of Mn

AP+QB=m-n
∵ A is the midpoint of MP and B is the midpoint of QN
∴MP+QN=2AP+2QB=2(m-n)
MN=MP+PQ+QN=2m-n

As shown in the figure, AB is the diameter of ⊙ o, and the chord CD ⊥ AB is at point E. (1) when AB = 10 and CD = 6, find the length of OE; (2) when the bisector of ⊙ OCD intersects ⊙ o at point P, when point C moves on the upper semicircle (excluding points a and b), for point P, the following three conclusions are drawn: ① the distance from CD remains unchanged; ② bisector the lower semicircle; ③ bisector dB______ Please prove it

(1) In RT △ OCE, from Pythagorean theorem, OE = oc2 − CE2 = 52 − 32 = 4; (2) it is proved that the connection op (as shown in Fig. 1), ∵ OC = OP, ∵ OC = 2 = ∠ 3, and ∵ OC = 2, ∵ op ⊥ a

Equations 1

11/2
2X

Given that the fixed point a (4,0), B is a moving point on the circle x ^ 2 + y ^ 2 = 4, and point P satisfies AP vector = 2PB vector, the trajectory equation of point P is obtained
It is helpful for the responder to give an accurate answer

Let P (x, y), B (x1, Y1)
It is known that the ratio of P-component vector AB is 2,
According to the fixed score point formula,
x=(4+2x1）/(1+2)=4/3+(2/3)x1
y=(0+2y1)/(1+2)=（2/3）y1
There are X1 = (3x-4) / 2 ①, Y1 = 3Y / 2 ②
B is a moving point on the circle x ^ 2 + y ^ 2 = 4, so X1 ^ 2 + Y1 ^ 2 = 4
Substituting (1) and (2) into (3), the result is (3x-4) ^ 2 + 9y ^ 2 = 16
p. S this is an ellipse, because it's inconvenient, it won't be converted to the standard form, which is very simple

It is known that the two of the equation 2x's square-3x-1 = 0 are X1 and x2. Solve the equation and find the value of (1) X1 (x2) to the second power + (x1) to the second power x2
(2) X2 of X1 + X1 of x2

x1＋x2=3/2,x1x2=－1/2(1)(x1)(x2)²＋(x1)²(x2)=(x1x2)(x1＋x2)=－3/4 (2)(x2/x1)＋(x1/x2)=[(x1)²＋(x2)²]/(x1x2)=[(x1＋x2)²－2(x1x2)]/(x1x2)=－13/2

Given the quadrilateral ABCD, a (2,1) B (- 1,2) C (- 2, - 3) d (1, - 2), find the quadrilateral ABCD with respect to the x-axis symmetric quadrilateral A1, B1, C1, D1
About quadrilateral Y-axis symmetry, quadrilateral A2, B2, C2, D2. Please teach me! Homework! Hurry up, it's drawing

The relationship between the two points of symmetry about x-axis is as follows:
The abscissa is equal and the ordinate is opposite to each other;
therefore
A1(2,-1)
B1(-1,-2)
C1(-2,3)
D1(1,2)
Connecting the four points is the figure;