Given that the solution set of inequality (A & # 178; - 4) x & # 178; + (a + 2) X-1 ≥ 0 on X is an empty set, what is the value range of real number a? Why do we discuss the case of a & # 178; - 4 = 0

Given that the solution set of inequality (A & # 178; - 4) x & # 178; + (a + 2) X-1 ≥ 0 on X is an empty set, what is the value range of real number a? Why do we discuss the case of a & # 178; - 4 = 0

Because the inequality mentioned in the question is not clear about whether it is a linear inequality of one variable or a quadratic inequality of one variable,
So we should discuss the case of a ^ 2 -- 4 = 0

Given that a and B are reciprocal, C and D are opposite, we can find the value of 4c-3ab + 4D

a. B is the reciprocal, then AB = 1
C. D is opposite to each other, then c + D = 0
4C-3AB+4D
=4(C+D)-3AB
=4*0-3*1
=0-3
=-3
It's a negative number three

Let X1 and X2 be the two roots of the equation 2x ^ 2 + 4x-3 = 0. Using the relationship between roots and coefficients, we can find the values of the following formulas: 1. (2x1 + 1) (2x2 + 1) 2. X1-x2

X1 + x2 = - 2x1x2 = - 3 / 21, the original formula = 4x1x2 + 2x1 + 2x2 + 1 = 4x1x2 + 2 (x1 + x2) + 1 = - 6-4 + 1 = - 92, (x1-x2) & sup2; = X1 & sup2; - 2x1x2 + x2 & sup2; = X1 & sup2; + 2x1x2 + x2 & sup2; - 4x1x2 = (x1 + x2) & sup2; - 4x1x2 = 4 + 6 = 10x1-x2 = - √ 10 or √ 10

Given that the function f (x) = 4x + m · 2x + 1 has and has only one zero point, then the value of real number m is______ ．

∵ f (x) = 4x + m · 2x + 1 has and only has one zero point, that is, the equation (2x) 2 + m · 2x + 1 = 0 has only one positive real root. Let 2x = t (T > 0), then T2 + MT + 1 = 0. When △ = 0, that is M2-4 = 0, ∵ M = - 2, t = 1 satisfies the meaning of the problem. When m = 2, t = - 1 does not satisfy the meaning of the problem, so the answer is: - 2

Until the quadratic equation of one variable (m-1) x ^ 2-2mx + M = 0 about X, find the value range of M
Express clearly

Because the equation is quadratic, M is not equal to 1

The intersection points of its image and two coordinate axes are (0,9) (- 1.0), respectively,

Axis of symmetry x = - B / 2A = - 5
Let y = ax & # 178; + BX + C
Substituting (0 9) (- 1 0) into
c=9
b=10a
y=ax²+10ax+9
Substituting (- 1 0) into
a-10a+9=0
-9a=-9
a=1
b=10
y=x²+10x+9

When x is equal to what, the result of the following formula is equal to 0? When x is equal to what, the result of the following formula is equal to 1? Formula: (48-4x) divided by 4

(48-4x) divided by 4 = 0, then 48-4x = 0, 48 = 4x = 12
(48-4x) divided by 4 = 1, then 48-4x = 4, 44 = 4x = 11

Is [15 times (the third power of x)] the most quadratic simple root under the root sign

It is not the simplest quadratic radical. Because one of the conditions of the simplest quadratic radical is that the exponent of every factor in the number to be squared is less than the root exponent, and the third power of X is greater than 2, this problem is not the simplest quadratic radical

Solve the equation x △ 3 + X △ 2 = 16

x/3+x/2=16
2x/6+3x/6=16
5x/6=16
5x=96
x=96/5

The square of complex 3A plus bracket 3A minus bracket 5A minus bracket 7a plus bracket 4a is equal to?

-3a^2+(3a-5a^2)-(7a^2+4a)
=-3a^2+3a-5a^2-7a^2-4a
=-15a^2-a