When the resistance wire with 100 Ω is electrified for 100s, the heat generated by the circuit is 400j, and the current passing through the circuit is 400j________ A?

When the resistance wire with 100 Ω is electrified for 100s, the heat generated by the circuit is 400j, and the current passing through the circuit is 400j________ A?

When the resistance wire with 100 Ω is electrified for 100s, the heat generated by the circuit is 400j, and the current passing through the circuit is 400j__ 0.2__ A .
∵ Q=I²Rt
∴ I²=Q/Rt=400/(100×100)=0.04
∴ I=0.2（A）

For two digits with a single digit of 5, the result of taking the square is regular: the square of 15 equals 225, and the square of 25 equals 265
It's OK to write 25 after 1. Does this rule hold for the square of two digits with a single digit of 5? Why? It is proved by complete square

Let X be a natural number from 1 to 9, then any two digit number with 5 can be expressed as (10x + 5), so its square is:
（10x+5）*（10x+5）=100x*x+100x+25=100*x*（x+1）+25,
That's the topic!

Connect the resistance R1 with a resistance value of 2 Ω and the resistance R2 with a resistance value of 5 Ω in parallel to the power supply of the circuit. The voltage ratio at both ends of r1r2 is () and the current ratio is（

Connect the resistance R1 with resistance value of 2 Ω and the resistance R2 with resistance value of 5 Ω in parallel to the power supply of the circuit. The voltage ratio at both ends of r1r2 is (1:1), and the current ratio is (5:2)

The natural numbers from 1 are grouped as follows: (1), (2,3,4), (5,6,7,8,9), (10,11,12,13,14,15,16) What is the fifth number of the 13th group?

According to the meaning of the question: the last number of each group is the square of the group number, so the last number of the thirteenth group is the square of 13, that is 132 = 169, one number in the first group, three numbers in the second group, five numbers in the third group, so the 13th group is 13 + 1 = 23, and because each group of numbers is an arithmetic sequence, the fifth number of the thirteenth group is 169-23 + 1 + 4 = 151. A: the fifth number of the 13th group is 151

The lamp and resistor are connected in series in the circuit. When calculating the voltage of the lamp, the total current * the resistance of the lamp is used. Why is the total current U / R Lamp + R resistor,

In a series circuit, the current through all components is the same
I total = I light = I resistance
But in the series circuit, the component voltage synthesis is equal to the total voltage of the circuit
U total = u Lamp + U resistance
So according to Ohm's law
U lamp = I lamp * r lamp = I Main * r lamp
I total = u total / (r Lamp + R resistor) = u lamp / R lamp = u resistor / R resistor

[30 / 7 + 4 / 5 + 9 and 1 / 5] / / 103.45 × 2 / 5 + 1.55 × 2 / 5-1.45
[7 / 10 + 1 / 6 + 11 / 30] × 30 87.45 × 1.01-87.45 6.07 × 89 + 60.7 × 1.1
Simple operation

[7 / 10 + 1 / 6 + 11 / 30] × 30 = 7 / 10 × 30 + 1 / 6 × 30 + 11 / 30 = 21 + 5 + 11 = 3787.45 × 1.01-87.45 = 87.45 × (1.01-1) = 87.45 × 0.01 = 0.87456.07 × 89 + 60.7 × 1.1 = 6.07 × 89 + 6.07 × 11 = 6.07 × (89 + 11) = 6.07 × 100

In the circuit as shown in the figure, the power supply voltage is 6V. When the switch is closed, the indication of the ammeter is 0.5A,
Calculation: 1. Current through resistor Q2. 2. Total resistance of the circuit. 3. Work done by current on resistor R1 after 10s

1. The current through R2 is I2 = u / r2 = 6 / 6 = 1a
The electric power of R2 is P2 = ui2 = 6 * 1 = 6W
2.R1=U/I1=6/0.5=12Ω
1 / R union = 1 / R1 + 1 / r2 = 1 / 12 + 1 / 6 = 1 / 4
Then the total resistance in the circuit is R and = 4 Ω
3. The work done by the current to the resistance R1 within 10s of power on is as follows:
W1=UI1t=6*0.5*10=30J

The number of integer solutions (x, y) of equation X3 + 6x2 + 5x = y3-y + 2 is ()
A. 0b. 1C. 3D. Infinity

The original equation can be reduced to X (x + 1) (x + 2) + 3 (x2 + x) = y (Y-1) (y + 1) + 2, ∵ the product of three consecutive integers is a multiple of 3, ∵ the left side of the above equation is a multiple of 3, while the right side is divided by 3 and the remaining 2, which is impossible. ∵ the original equation has no integer solution

How to read the unit of conductivity US / cm? How to convert it to other units?

Micro Siemens per square centimeter is reciprocal to resistance. 1s = 1 / 1 Ω
S is read west or Siemens. 1s = 1000 μ s

1-2x of - 2x = 2x & # 178; - X of

The denominator is the product of - X and the molecule of - x to the square of 2x