Given that the tangent of the curve y = ln (x-2a) √ (1 ax) at x = 0 is parallel to the X axis. 1. Find the value of A. 2. Find the tangent and normal equation of the curve at x = 0

Given that the tangent of the curve y = ln (x-2a) √ (1 ax) at x = 0 is parallel to the X axis. 1. Find the value of A. 2. Find the tangent and normal equation of the curve at x = 0

If the title is not clear, what is this?

(x-2)(x-3)+2(x-5)(x+6)-3(x^2-7x+12)
Where x = - 5 / 2

(x-2)(x-3)+2(x-5)(x+6)-3(x^2-7x+12)
=x^2-5x+6+2x^2+2x-60-3x^2+21x-36
=18x-90
=18*(-5/2)-90
=-45-90
=-135

It is known that the function y = x & # 178; + 2aX + 2 of X is on - 5 ≤ x ≤ 5. When a is a real number, we can find the maximum value of the function

y=x²+2ax+2=(x+a)²+2-a²
Vertex abscissa x = - A
Classification discussion:
-When A5, the function increases monotonically, and when x = 5, the function has the maximum value ymax = 25 + 10A + 2 = 10A + 27
When 0 ≤ - a ≤ 5, that is - 5 ≤ a ≤ 0, when x = - 5, the function has the maximum value ymax = 27-10a
When - 5 ≤ - A

The difference between a number and its reciprocal is 14 and 4 / 15
What's the number
Can you make it clear?
I want the results

It's not an integer at all

If the three roots of equation (x-1) (x2 + 8x-3) = 0 are x1, X2 and X3 respectively, then the value of x1x2 + x2x3 + x3x1 is ()
A. 5B. -5C. 11D. -11

∵ if the three roots of equation (x-1) (x2 + 8x-3) = 0 are x1, X2, X3, ∵ X1 = 1, X3 + x2 = - 8, x3 · x2 = - 3, then x1x2 + x2x3 + x3x1 = X1 (x2 + x3) + x2x3 = - 3-8 = - 11

The function f (x) defined on R satisfies that f (f (x) + X & # 178; - x + 2) + F (x) + X & # 178; - x + 2 = 0, G (x) = f (x) + X has and has only one zero point
Find the expression of F (x), if the function H (x) = | MF (x) - (M + 2) x + M & # 178; + M-1 monotonically increases on [0,2], find the value range of M

Let the unique zero of G (x) be x0, then f (x0) + x0 = 0
g[f(x)+x^2-x+2]=f[f(x)+x^2-x+2]+f(x)+x^2-x+2=0
It shows that f (x) + x ^ 2-x + 2 = x0, where x = x0 and f (x0) + x0 = 0 can be used to calculate x0
X0 = 1 or 2 (2 can be rounded off according to the unique zero point of G (x))
So, f (x) + x ^ 2-x + 2 = 1, find f (x)
What is the vertical bar following the equal sign of the expression H (x)

It is known that the quadratic equation mx2-3 (m-1) x + 2m-3 = 0 (M is a real number) of X (1) if the equation has two unequal real roots, find the value range of M; (2) prove that no matter what the value of M is, the equation always has a fixed root; (3) if M is an integer and both roots of the equation are positive integers, find the value of M and all roots of the equation

(1) ∵△ = b2-4ac = [- 3 (m-1)] 2-4m (2m-3) = (M-3) 2, ∵ equation has two unequal real roots, ∵ (M-3) 2 > 0 and & nbsp; m ≠ 0, ∵ m ≠ 3 and & nbsp; m ≠ 0,