If the cube of the fourth power of the polynomial x * y to the nth power - 2x is the same degree as that of the fifth power of the polynomial - 1 / 3 x - 3Y + 2, then The value of n-2N + 3n-4n + 5n-6n +... + 99n-100n

If the cube of the fourth power of the polynomial x * y to the nth power - 2x is the same degree as that of the fifth power of the polynomial - 1 / 3 x - 3Y + 2, then The value of n-2N + 3n-4n + 5n-6n +... + 99n-100n

∵ if the cube of the fourth power of the polynomial x * y to the nth power - 2x is the same degree as the fifth power of the polynomial - 1 / 3 x - 3Y + 2,
∴4+n=5
n=1
∴n-2n+3n-4n+5n-6n+...+99n-100n
=1-2+3-4+5-6+7-8+9-10+.99-100
=-50

Using simple calculation: (1-1 / 2 ^ 2) (1-1 / 3 ^ 2) (1-1 / 4 ^ 2) （1-1/10^2）
It's due on Monday

（1-1/2^2）（1-1/3^2）（1-1/4^2）… （1-1/10^2） =（2²-1/2²)(3²-1/3²)… (10²-1/10²)=(2+1)(2-1)/2²x(3+1)(3-1)/3²… (10+1)(10-1)/10²=1/2x11/10=11/20

How to calculate 2.02 * 18.5 simple operation?

2.02*18.5
=(2+0.02)*28.5
=2*18.5+0.02*18.5
=37+0.37
=37.37

Known arithmetic sequence an, tolerance greater than 0, A1 ^ 2 = (a11) ^ 2
Then the first n terms of sequence an and the number of terms n when Sn reaches the maximum are

Because A1 ^ 2 = (a11) ^ 2
So A1 = - a11
That is - A1 = a1 + 10d
The result is: a1 + 5D = 0 = A6
So the sixth term = 0
That is to say, when Sn reaches the maximum, the number of items n is 5 or 6

The scores of 45 ° 36 ′ - 25 ° 11 ′ and 42 ° 22 ′ - 18 ° 36 were calculated

45°36′-25°11′
=20°25'
42°22′-18°36'
=41°82'-18°36'
=23°46'

a²＋b²=2ab?

∵(a-b)²=0
∴a²＋b²-2ab=0
∴a²＋b²=2ab
When a = B, a & # 178; + B & # 178; = 2Ab

Fill the nine numbers - 8, - 6, - 4, - 2, 0, 2, 4, 6 and 8 into the nine squares in the graph, so that the sum of three numbers in each row, three numbers in each column and three numbers in diagonal angle is 0

As shown in the figure:

The equations 3S + 2T = 42s-3t = 7 are solved by addition subtraction elimination method

3S + 2T = 4, 2s-3t = 7
(3S + 2t) * 3 = 4 * 3, i.e. 9s + 6T = 12
（2s-3t）*2=7*2 4s-6t=14
So: 9s + 6T + 4s-6t = 12 + 14 13s = 26 S = 2
If we bring in the original formula, we get t = - 1

It is known that the remainder of polynomial f (x) divided by (x-1), (X-2) is 1 and 2 respectively. Try to find the remainder of polynomial f (x) divided by (x-1) * (X-2)
There are no errors in this issue

[solution] it is not difficult to know that the remainder of F (x) divided by (x-1) (X-2) must be a linear expression, so it can be set as ax + B
f(x)＝(x－1)(x－2)g(x)+ax+b
According to the conditions of the title, when x = 1, f (x) = 1; when x = 2, f (x) = 2
a+b=1, 2a+b=2
The solution is a = 1, B = 0, so the remainder is X

If the algebraic formula 2x ^ 2 + 3x + 1 = 6, then the value of the algebraic formula 4x ^ 2 + 6x-1 is?
A 2
B 3
C16
D17

2x²+3x=6-1=5
Double two on both sides
4x²+6x=10
4x²+6x-1=10-1=9